Word | Frequency | Number of right neighbors | Number of left neighbors | Ratio |
---|---|---|---|---|
empleo | 315 | 19 | 1 | 19.0000 |
Vendo | 174 | 19 | 1 | 19.0000 |
B/. | 158 | 19 | 1 | 19.0000 |
pero | 633 | 34 | 2 | 17.0000 |
acá. | 86 | 12 | 1 | 12.0000 |
El | 2689 | 218 | 19 | 11.4737 |
La | 2295 | 198 | 19 | 10.4211 |
Como | 187 | 10 | 1 | 10.0000 |
Los | 895 | 70 | 8 | 8.7500 |
Las | 582 | 52 | 6 | 8.6667 |
Esta | 353 | 25 | 3 | 8.3333 |
A | 386 | 25 | 3 | 8.3333 |
porque | 396 | 24 | 3 | 8.0000 |
Casas | 250 | 8 | 1 | 8.0000 |
Para | 511 | 37 | 5 | 7.4000 |
requisitos | 100 | 7 | 1 | 7.0000 |
totales | 200 | 14 | 2 | 7.0000 |
Este | 474 | 26 | 4 | 6.5000 |
artículo | 459 | 32 | 5 | 6.4000 |
Si | 369 | 25 | 4 | 6.2500 |
Word | Frequency | Number of right neighbors | Number of left neighbors | Ratio |
---|---|---|---|---|
Agrega | 325 | 1 | 13 | 0.0769 |
oferta | 336 | 1 | 10 | 0.1000 |
grupo | 126 | 1 | 10 | 0.1000 |
RAH | 65 | 1 | 10 | 0.1000 |
documento | 88 | 1 | 9 | 0.1111 |
aquellos | 76 | 1 | 7 | 0.1429 |
concepto | 112 | 1 | 7 | 0.1429 |
ejemplo | 148 | 1 | 7 | 0.1429 |
tipos | 44 | 1 | 6 | 0.1667 |
ministro | 64 | 1 | 6 | 0.1667 |
fin | 167 | 2 | 12 | 0.1667 |
Puedes | 87 | 1 | 6 | 0.1667 |
años | 1460 | 16 | 94 | 0.1702 |
m² | 305 | 4 | 23 | 0.1739 |
dicho | 124 | 2 | 11 | 0.1818 |
domingo | 54 | 1 | 5 | 0.2000 |
EE | 85 | 1 | 5 | 0.2000 |
Actualizado | 285 | 1 | 5 | 0.2000 |
queso | 24 | 1 | 5 | 0.2000 |
grado | 45 | 1 | 5 | 0.2000 |
In this subsection, we compute the ratio of the number of right neighbors and the number of left neighbors. Again, we look for words with extreme ratios:
Data for first table:
select word,w.freq,aa.cnt, bb.cnt,aa.cnt/bb.cnt as r from words w, (select w1_id,count(c.w2_id) as cnt from co_n c where w1_id>100 group by w1_id) aa, (select w2_id,count(c.w1_id) as cnt from co_n c where w2_id>100 group by w2_id) bb where w_id=aa.w1_id and aa.w1_id=bb.w2_id order by r desc limit 20;
Diagram data:
select aa.cnt, bb.cnt from (select w1_id,count(c.w2_id) as cnt from co_n c where w1_id>100 group by w1_id) aa, (select w2_id,count(c.w1_id) as cnt from co_n c where w2_id>100 group by w2_id) bb where aa.w1_id=bb.w2_id;
5.1.7.1 Number of NN co-occurrences vs. Frequency I
5.1.7.2 Number of NN co-occurrences vs. Frequency II